Physics Question #50 – JEE-MAIN 2025

Question

The electric field in a region is given by E = (2i + 4j + 6k) x 10^3 N/C. The flux of the field through a rectangular surface parallel to x-z plane is 6.0 Nm^2C^-1. The area of the surface is _________ cm^2.

Accepted Answer

The correct answer is Option 15. Full mathematical solution steps and hints are accessible in the interactive StemCET workspace.

Physics Question 50 – JEE-MAIN 2025

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