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Chemistry Question 62 – JEE-MAIN 2025

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Formation of Na4[Fe(CN)5NOS], a purple coloured complex formed by addition of sodium nitroprusside in sodium carbonate extract of salt indicates the presence of :

This question relates to a specific qualitative test used to identify a particular anion.

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Ninja Strategy•Recall Specific Qualitative Test

Recognizing the sodium nitroprusside test as a specific indicator for sulphide ions allows for direct identification of the correct answer without considering other options.

Step 1: Identify the Reagent and Product✦ Active

The reagent used is sodium nitroprusside, Na2[Fe(CN)5NO]. The product formed is a purple coloured complex, Na4[Fe(CN)5NOS].

Step 2: Recall the Specific Test○ Expand

The formation of a purple complex when sodium nitroprusside is added to a sodium carbonate extract is a characteristic test for the presence of sulphide ions.

Step 3: Write the Chemical Reaction○ Expand
Na2[Fe(CN)5NO]+Na2S→Na4[Fe(CN)5NOS]

This reaction confirms that the sulphide ion (S2−) is responsible for the formation of the purple complex.

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