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Chemistry Question 122 – AP-EAMCET 2026

The de Broglie wavelength associated with a pebble of mass 6.63 g travelling with velocity x ms1 is 1024 nm. What is the value of x? (h=6.63×1034 Js)

Remember that particles can exhibit wave-like properties, and their wavelength is inversely proportional to their momentum.

Step 1: Identify Given Values and Required Formula✦ Active

The problem asks for the velocity (x) of a pebble given its mass (m), de Broglie wavelength (λ), and Planck's constant (h). The relevant formula is the de Broglie wavelength equation:

λ=hmv
💡 Teacher's Secret Hint

Ensure all units are consistent (SI units are preferred) before plugging values into the formula. Pay attention to powers of 10 in unit conversions.

Step 2: Convert Units to the SI System○ Expand

Convert the given mass from grams to kilograms and the de Broglie wavelength from nanometers to meters to ensure consistency with Planck's constant in Joules-seconds.

m=6.63 g=6.63×103 kg
λ=1024 nm=1024×109 m=1033 m
h=6.63×1034 Js
💡 Teacher's Secret Hint

Recall that 1 g=103 kg and 1 nm=109 m. Common conversion errors can lead to incorrect powers of 10.

Step 3: Rearrange the Equation and Substitute Values○ Expand

Rearrange the de Broglie wavelength equation to solve for velocity (v). Then, substitute the given and converted values into the equation.

v=hmλ
v=6.63×1034 Js(6.63×103 kg)×(1033 m)
v=6.63×10346.63×10333
v=6.63×10346.63×1036
v=1×1034(36)
v=1×102 ms1
💡 Teacher's Secret Hint

Be careful with exponent arithmetic, especially when dividing powers of 10. Subtracting a negative exponent is equivalent to adding a positive exponent.

Step 4: State the Final Answer○ Expand

The calculated velocity is 1×102 ms1. Therefore, the value of x is 1.0×102. This corresponds to option 2.

x=1.0×102
💡 Teacher's Secret Hint

Always double-check the units in the final answer. Velocity should be in ms1.

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